b^2x+b^2=b^4+bx

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Solution for b^2x+b^2=b^4+bx equation: 


Simplifying
b2x + b2 = b4 + bx

Reorder the terms:
b2 + b2x = b4 + bx

Reorder the terms:
b2 + b2x = bx + b4

Solving
b2 + b2x = bx + b4

Solving for variable 'b'.

Reorder the terms:
-1bx + b2 + b2x + -1b4 = bx + b4 + -1bx + -1b4

Reorder the terms:
-1bx + b2 + b2x + -1b4 = bx + -1bx + b4 + -1b4

Combine like terms: bx + -1bx = 0
-1bx + b2 + b2x + -1b4 = 0 + b4 + -1b4
-1bx + b2 + b2x + -1b4 = b4 + -1b4

Combine like terms: b4 + -1b4 = 0
-1bx + b2 + b2x + -1b4 = 0

Factor out the Greatest Common Factor (GCF), 'b'.
b(-1x + b + bx + -1b3) = 0


Subproblem 1
Set the factor 'b' equal to zero and attempt to solve:

Simplifying
b = 0

Solving
b = 0

Move all terms containing b to the left, all other terms to the right.

Simplifying
b = 0

Subproblem 2
Set the factor '(-1x + b + bx + -1b3)' equal to zero and attempt to solve:

Simplifying
-1x + b + bx + -1b3 = 0

Reorder the terms:
b + bx + -1b3 + -1x = 0

Solving
b + bx + -1b3 + -1x = 0

The solution to this equation could not be determined.

This subproblem is being ignored because a solution could not be determined.
Solution
b = {0}

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